Suppose X has a Binomial(n,p) distribution. Then what is its moment generating function

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Suppose $X$ has a $Binomial(n,p)$ distribution. Then its moment generating function (MGF) $M_{X}(t)$ is $(pe^t+(1-p))^n$.

But what is the MGF of $-X$, i.e. $M_{-X}(t)=\mathbb{E}(e^{-tX})$?

Is it $M_{-X}(t)$= $(pe^{-t}+(1-p))^n$?

Or should the notation be $M_{X}(-t)$ and let $X$ be positive?