Suppose $y $ satisfies D.E. $dy/dx=y^2$

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Describe the behaviour of the following initial conditions:

$y (0)=0$, $y (0)=0.01$, $y (0)=-0.01$

Ans: if I solve for $y $ first I get: $y=1/(c-x) $

$y (0)=0$ gives me a vertical asymptote.

2nd and 3rd conditions give my constant 100 and -100 values respectively. Am I correct? Is that all I'm supposed to describe?