Normally, in theoretical demonstrations, $U$ has size $(m, n)$ instead of $(m, r)$. Why is that so? Is there a reason why we include a basis for the nullspace as well in the matrices $U$ and $V$?
2026-03-27 07:49:32.1774597772
SVD - why do we complete matrices $U$ and $V$ with the vectors that form a basis for the nullspace?
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