I am looking for any complex number solutions to the system of equations:
$$\begin{align} |a|^2+|b|^2+|c|^2&=\frac13 \\ \bar{a}b+a\bar{c}+\bar{b}c&=\frac16 (2+\sqrt{3}i). \end{align}$$
Note I put inequality in the tags as I imagine it is an inequality that shows that this has no solutions (as I suspect is the case).
This is connected to my other question... I have found that $(4,1,1)/6$ and $\mu=(2,2+\sqrt{3}i,2-\sqrt{3}i)/6$ are square roots of $(2,1,1)/4$ in $(\mathbb{C}\mathbb{Z}_3,\star)$ but am trying to understand why $\mu$ is not positive in the C*-algebra when, for example, $(14,-6+5i,-6-5i)$ is.
By Cauchy-Schwarz, we must have$$\left(|a|^2+|b|^2+|c|^2 \right) \left(|\overline{c}|^2+|\overline{a}|^2+|\overline{b}|^2 \right) \ge \left| a\overline c + b\overline a + c\overline b\right|^2$$ $$\implies \frac19 \ge \frac1{36}|2+\sqrt3 \; i|^2 = \frac7{4\cdot9}$$ which is obviously not possible...