$x^2+y^2<=81$
$y<x$
Is this correct? My answer: (-9sqrt(2)/2,-9sqrt(2)/2), (9sqrt(2)/2,9sqrt(2)/2)
2026-03-27 07:49:33.1774597773
System of inequalities. Points of intersection?
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Hints:
Notice $x^2 + y^2 \leq 81 = 9^2 $ is the set of all $(x,y)$ that lies inside a circle(centered at the origin) of radius $9$, and including its boundary.
and $y < x $ is the set of all points that lie below the the $45^0$ degrees line excluding the points in the diagonal.