tan(x) from sin(x) and cos(x)

Question

Given sin(x) and cos(x) can I determine the value of tan(x) without using tan itself (i.e: no sin^-1(sin(x)) etc)?

Answer 1

Yes: $$ \tan x = \frac{\sin x}{\cos x} $$

Answer 2

We have $\tan x=\frac{\sin x}{\cos x}$.