Tangent vector to a curve.

Question

Given the curve $$r(t)=(t,t^2,2)$$ I have to find the tangent vector to $r$ at $Q(1,1,2)$. From the coordinates of $Q$, I know that $t=1$, so the tangent vector is $$r'(1)=(1,2,0)$$ But when I plot the curve $r$ and the vector $r'(1)-r(1)=(0,1,-2)$ in Geogebra it's not tangent at all. What's wrong?

Answer 1

Note that you must plot the vector $(1,2,0)$ starting at $Q(1,1,2)$ (you have possibly drawn it starting from $(0,0,0)$). A sketch is as follows