Taylor polynomial for $f(x, y) = \arctan(\frac{y}{x})$

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Given the function $f(x, y) = \arctan(\frac{y}{x})$ defined for $(x,y)$ with $x>0$, how can we find Taylor polynomial in point $x_0=0$? As I understood, Taylor polynomials for $n=1$ for functions with two variables are the same as tangent plane, right?

In addition, how can we prove that $f$ doesn't have a limit value in point $x_0 (0, 0)$?