Taylor Series - when to stop the accumulation or orders? - Numeric Analayze - rate of convergence

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Let us say we have the sequence: $$\epsilon_{n+1}=\epsilon_n-\frac{1+\epsilon_n-e^{2\epsilon_n}}{1-2e^{2\epsilon_n}}$$ In order to find the rate of convergence, I have to do taylor series here.
Problem is, How do I know when do I stop? I tried to take the first order of $e^{2\epsilon_n}$ and at the end I received: $$\epsilon _{n+1}=\frac{4\epsilon_n\left(\epsilon_n-1\right)}{4\epsilon_n-1}$$ Which means my Rate of convergence should be 1 with $|A|=k$, for some k constant.
Although by the answer, the rate of convergence is 2. To fix this, if I took the taylor series up to the second term, which means: $$e^{2\epsilon_n}=1+2\epsilon_n+\frac{\left(2\epsilon_n\right)^2}{2!}$$

Then I will get the good answer, which rate of convergence of 2.

What is the reason of this? when do I know where to stop at taylor series so my rate of convergence rate will be accurate?