The BOOK proof of the quadratic reciprocity law - need explanation about prime field of finite field

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There is a sentence:

Let $p$ and $q$ be different odd primes, and consider the finite field $F$ with $q^{p-1}$ elements. Its prime field is $\mathbb{Z}_q$, whence $qa=0$ for any $a\in F$.

Why is it so? Thank you.