Let $N(x) = f^{-1}(x)$, and $f(1) = 3$
Is $N'(3) =\frac{1}{f'(3)}$ or $\frac{1}{f'(1)}$?
In general, \begin{align} \left(f^{-1}\right)'(x) &= \dfrac{1}{f'\left(f^{-1}(x)\right)}. \end{align} I leave it to you to plug in everything carefully.
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In general, \begin{align} \left(f^{-1}\right)'(x) &= \dfrac{1}{f'\left(f^{-1}(x)\right)}. \end{align} I leave it to you to plug in everything carefully.