Let $R$ be a Bezout domain with quotient field $K$, $L$ an arbitrary extension field of $K$, and $\overline{R}$ the integral closure of $R$ in $L$. Is $\overline{R}$ a Prüfer domain? If the answer is negative, I wonder under what conditions it would be a Prüfer domain?
2026-03-28 04:45:23.1774673123
The integral closure of Bezout domains in arbitrary field extensions is Prüfer?
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