Let $U \subset \mathbb{R}^n$ be an open set and $f:U \to \mathbb{R}$ a continuous function.
The function $g:U \to \mathbb{R}$ is given by $$g(x)=\int_{0}^{f(x)}\!\left(t^2+1\right)\mathrm dt$$
If $g$ is in $C^1$ then is $f$ in $C^1$ too?
Let $U \subset \mathbb{R}^n$ be an open set and $f:U \to \mathbb{R}$ a continuous function.
The function $g:U \to \mathbb{R}$ is given by $$g(x)=\int_{0}^{f(x)}\!\left(t^2+1\right)\mathrm dt$$
If $g$ is in $C^1$ then is $f$ in $C^1$ too?
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