The Normal Bundle of a level set is trivial

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Let $M,N$ be manifolds and $f:N\to M$ an embedding. For every $p\in N$, $df_p:T_pN\to T_pM$ shows that $T_pN\subset T_pM$. For every $p\in N$, define the normal space of $N$ in $M$ at $p$ as $$ (\eta_{N|M})_p:=\frac{T_pM}{T_pN}. $$ Gluing together all these spaces, we obtain $$ \eta_{N|M}:=\frac{TM|_N}{TN} $$ the normal bundle of $N$ in $M$.

The Tubular Neighbourhood Theorem holds.

Let $S$,$M$ be manifolds without boundary, $i:S\to M$ an embedding. Then there exists

  • $T$, neighborhood of $i(S)$ in $M$
  • $v:\eta_{S|M}\to T$ such that $i=v\circ s_0$, where $s_0:S\to \eta_{S|M}$ is the zero section.

Now, let $M$ be a manifold with our boundary, $f:M\to\mathbb{R}$ be a smooth function, $y\in Reg(f)$ and $N$ be a connected component of $f^{-1}(y)$. I have to prove that $\eta_{N|M}$ is trivial.

I can't understand how to proceed. First of all because the definition of normal bundle is not clear to me at all.

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Showing that the normal bundle is trivial is the same thing as demonstrating a nonvanishing global section of $\eta$ (since it's one-dimensional). At each point $n \in N$ let $v \in (TM/TN)_n$ be the unique vector with $df(v) = 1 \in T_y \Bbb R$. (Why is there a unique such vector?) This is a continuous section of the normal bundle, as you can check in local coordinates (pick a slice chart for the submersion). Because this section cannot vanish anywhere (it maps to something nonzero!), this is the desired trivializing section.