The number of integer triplets $(a,b,c)$ such that $a+b\cos(2x)+c\sin^2x=0$ for all $x$

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The number of integer triplets $(a,b,c)$ such that $$a+b\cos(2x)+c\sin^2x=0\quad\text{for all $x$}$$ is

  • (A) $0$
  • (B) $1$
  • (C) $3$
  • (D) infinitely many

I tried to break $\cos 2x$ and write it in sine form, but got confused.

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Hint: $\cos{2x} = 1-2\sin^2{x}$.