The side of an equilateral triangle ABC is 4 times square root of 3. The triangle bisectors AM and CN meet at point O. Find vectors AM and CO

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I got AM by using the pythagorean theorem but I can't seem to figure out how to find CO

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Hints:

  • $\dfrac{AM}{AB}=\sin\frac\pi 3$,
  • In a triangle, the medians meet at the 2/3 of their lengths.