Tits' field of 1 element philosophy for $G_2$

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It was my understanding that taking the formula for the number of elements in a finite group of Lie type over a field with $q$ elements (expressed as a function of $q$) and substituting $q = 1$, we will obtain the number of elements of the corresponding Weyl group. However the Wikipedia page on $G_2$ tells me that the finite group $G_2(q)$ has $q^6(q^6-1)(q^2-1)$ elements. It is not hard to see that when substituting $q = 1$ in this polynomial we obtain a number that is far from the 'correct' answer of $12$. What am I missing?