This question is regarding my previous post
where the hint was given by Moo to find the laplace transform of $\frac{-sin~t}{t}$..
My sol:
$\mathcal{L}(-sin ~t) = \frac{-1}{s^2 +1}$ and thus
$\mathcal{L}(\frac{-sin ~t}{t}) = \int_{s}^{\infty}\frac{-1}{s^2 +1}$ which implies that
$\mathcal{L}(\frac{-sin ~t}{t}) =\frac{\pi}{2} + tan^{-1}s$
which gives $k = \frac{\pi}{2}$.
Is my answer correct? If not then help me. Thanks for the time and help.