What would be a sequence of partitions of [0,1] to show that the function
$f(x)$ = \begin{cases} 0, & \text{if $x$ $\in$[0,1]$\cap$$Q^c$} \\ -x, & \text{if $x$$\in$[0,1]$\cap$$Q$} \end{cases}
is not of bounded variation on [0,1]?
2026-03-26 20:39:52.1774557592
To show that a function is not of bounded variation on [0,1]
242 Views Asked by Bumbble Comm https://math.techqa.club/user/bumbble-comm/detail AtRelated Questions in REAL-ANALYSIS
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