The torque $M$ of a force $\overrightarrow{F}$ as for the point $O$ is defined as the product of the magnitude of the force $\overrightarrow{F}$ and the perpendicular distance of the point $O$ and the action line of $\overrightarrow{F}$.
The torque vector $\overrightarrow{M}$ is the vector of magnitude $M$ of which the direction is perpendicular to the plane of $O$ and $\overrightarrow{F}$, the orientation is determined by the right-hand rule.
Show that $\overrightarrow{M}=\overrightarrow{R} \times\overrightarrow{F}$, where $\overrightarrow{R}$ is a random vector with start point the $O$ and end point on the action line of $\overrightarrow{F}$.
Could you give me some hints how we could show this??
Hint: Find the magnitude of the cross product and think about what rule you use to find the direction of the cross product of two vectors.