Word Problem:
A track and field runner saves 1 hour by covering 112 km at a rate which is 2 kmph greater than the usual rate. How many hours does he usually take to travel this distance?
Word Problem:
A track and field runner saves 1 hour by covering 112 km at a rate which is 2 kmph greater than the usual rate. How many hours does he usually take to travel this distance?
Hints:
If the usual rate is $r$ (kph), then the faster rate is ...
At the usual rate it takes ... (time) to cover the distance. (In terms of $r$.)
At the faster rate it takes ... (time) to cover the distance.
Set up and solve an equation.
Final thought: Wow, that is a long distance to run!