Transitivity of a binary relation

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Given: The domain of the relation $R$ is $\{a, b, c, d\}.$ $R = \{(a, b), (b, a), (c, d), (d, c)\}.$

Why is this relation not transitive? According to my textbook,

By definition

R is transitive if and only if for every three elements, x, y, z ∈ A, if xRy and yRz, then it must also be the case that xRz.

and R is not transitive when

The situation that is not allowed in a transitive relation is for there to be an x, y, and z , such that xRy and yRz are true but xRz is not true. Notice that the definition of transitive is a universal statement. If any x, y, and z in the domain have the forbidden pattern of xRy and yRz but not xRz, then the relation is not transitive. If there is no triple x, y, and z that has the forbidden pattern, then the relation is transitive.

I thought it was transitive because it says "for every three elements", if $xRy$ and $yRz$ then $xRz$. Since there are no three elements where the situation $xRy$ and $yRz$ even occurs, I assumed it would be considered transitive.

Furthermore, the second excerpt states that "If there is no triple x, y, and z that has the forbidden pattern, then the relation is transitive." And as far as I can see, there is no triple, with the forbidden pattern.

I am confused.

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Note that the definition does not say "for every three distinct elements". In the given example, with $x:=a$, $y:=b$, and $z:=a$, we see that $xRy$ and $yRz$, but not $xRz$ (i.e., $aRb$ and $bRa$, but not $aRa$).

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It's not transitive, because you have $a\,R\,b$ and $b\,R\,a,$ and by transitivity that implies $a\,R\,a.$ But $a\,R\,a$ is not true.