Find the values of x between 0 and 360 inclusive that satisfy
$$x\sin x - \cos x = 1$$
I tried squaring it but i get
$$(x^2-1)\sin x = 2x\sin x\cos x$$
which I can't really solve.
Find the values of x between 0 and 360 inclusive that satisfy
$$x\sin x - \cos x = 1$$
I tried squaring it but i get
$$(x^2-1)\sin x = 2x\sin x\cos x$$
which I can't really solve.
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