Trigonometric functions separates the points

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Consider $s_n(x) := e^{inx}$ for any $n \in \mathbb{Z}$, and define ${\cal A} := span\{s_n\}_{n \in \mathbb{Z}}$, I think there is a theorem says that ${\cal A}$ is dense in $(C([-\pi,\pi],\mathbb{C}),||\cdot||_{\infty})$

To prove this theorem, we need to invoke Stone-Weistrass Theorem, one thing I don't understand is that why ${\cal A}$ separates the points over $[-\pi,\pi]$? For any $f \in {\cal A}$ we must have $f(-\pi) = f(\pi)$ right?

Thanks for your help!

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That's an excellent catch. Indeed, the trigonometric polynomials are dense in the space of periodic functions on an interval. Meaning that actually, trig polynomials are dense in the space $$ \left(C(S^1,\mathbb{C}),||\cdot||_\infty\right) $$