Trigonometry / reference angle

Question

My question is how to find the reference angle for the following angle?

Θ=7π/6

what i get was $\dfrac{7\pi}{6}-\dfrac{6\pi}{6}= -\dfrac{11\pi}{6}$ i'm still unsure im doing it correctly

Answer 1

By definition, a reference angle is an ACUTE angle formed by the terminal side of the angle and the horizontal axis. From your figure the reference angle is $7\pi/6-\pi=\pi/6$.