Given the following statements:
$\forall\, x,y \in \Bbb Q \quad \exists\, z \in \Bbb Q $ $\;$ $ : \left(x<z<y\right) \vee \left(x>z>y\right)$.
$\forall \, x \in \Bbb R \quad \exists\,y\in \Bbb R : y^2= x$
$\forall \, x \in \Bbb R^+ \quad \exists\,y\in \Bbb R : y^2= x$
$\forall \, x \in \Bbb Z : | x | > 0$
$\forall\, x,y \in \Bbb Q : \left(x<y \rightarrow \exists\, z \in \Bbb Q: x<z<y \right)$
$\forall \, x \in \Bbb N \quad \exists\, y \in \Bbb N : x>y$
$\forall \, x \in \Bbb R \quad \exists\, y \in \Bbb R : y^2=|x|$
$\forall \, x \in \Bbb Z \quad \exists\, y \in \Bbb Z: x \lt y \lt x+1 $
$\exists\,x \in \Bbb N \quad \forall\, y \in \Bbb N : x\le y$
$\forall \, x,y \in \Bbb N \quad \exists \, z \in \Bbb N: x+z=y$
$\forall\,x\in\Bbb R\quad\exists\,y\in\Bbb R:x\lt y \lt x+1$
$\forall\,a,b\in\Bbb Q\quad\exists\,x\in\Bbb Q:ax=b$
$\forall\,x\in\Bbb Z\quad\exists\,y\in\Bbb Z : x\gt y$
$\forall\,x,y\in\Bbb Z\quad\exists\,z\in\Bbb Z:x+z=y$
$\forall\,a,b\in\Bbb Z\quad\exists\,x\in\Bbb Z:ax=b$
$\forall\,m\in\Bbb Z\quad\exists\,q\in\Bbb Q:m\lt q\lt m+1$
list which are true.
Only $2,6$ and $8$ are false, correct?
The complete list of true statements is:
3) $\forall \, x \in \Bbb R^+ \quad \exists\,y\in \Bbb R : y^2= x$
5) $\forall\, x,y \in \Bbb Q : \left(x<y \rightarrow \exists\, z \in \Bbb Q: x<z<y \right)$
7) $\forall \, x \in \Bbb R \quad \exists\, y \in \Bbb R : y^2=|x|$
9) $\exists\,x \in \Bbb N \quad \forall\, y \in \Bbb N : x\le y$
11) $\forall\,x\in\Bbb R\quad\exists\,y\in\Bbb R:x\lt y \lt x+1$
13) $\forall\,x\in\Bbb Z\quad\exists\,y\in\Bbb Z : x\gt y$
14.) $\forall\,x,y\in\Bbb Z\quad\exists\,z\in\Bbb Z:x+z=y$
16) $\forall\,m\in\Bbb Z\quad\exists\,q\in\Bbb Q:m\lt q\lt m+1$
For each the others (that are not true), you need only find a single counterexample in which the statement is false: $\color{red}{1, 2,4,6,8,10, 12, 15}$
Note that $1)$ is false whenever $x = y$. It would be true, however, if we have $$\forall x, y \in \mathbb Q((x\neq y) \rightarrow \exists z \in \mathbb Q (x\lt z \lt y)\lor (x\gt z\gt y))$$
$(12)$ is false, if we take $a = 0, b= 2$, e.g., but is true if we state 12) $\forall\,a,b\in\Bbb Q((a\neq 0)\rightarrow\exists\,x\in\Bbb Q(ax=b))$