Let $X$ a space, and $E$ an multiplicative cohomology theory represented by a ring spectrum $K$, i.e. $E^\bullet(X)=[X,K]$. Also let $A$ be a local system of abelian groups. Cohomology with local coefficients or twisted cohomology $E^\bullet(X;A)$ can apparently be described as the set of sections of a bundle over $X$ with fiber $K$. Can you elucidate this construction for me? For example, let $A$ be the orientation sheaf of a manifold $M$, and consider ordinary cohomology with these coefficients. What is my bundle of $K(G,n)$'s? Also can you explain how we understand the twisting as a map to the Picard group of $K$? References welcome
2026-03-25 23:43:59.1774482239
Twisted cohomology as sections of bundle of Eilenberg-Maclane spaces
599 Views Asked by Bumbble Comm https://math.techqa.club/user/bumbble-comm/detail At
1
There are 1 best solutions below
Related Questions in ALGEBRAIC-TOPOLOGY
- How to compute homology group of $S^1 \times S^n$
- the degree of a map from $S^2$ to $S^2$
- Show $f$ and $g$ are both homeomorphism mapping of $T^2$ but $f$ is not homotopy equivalent with $g.$
- Chain homotopy on linear chains: confusion from Hatcher's book
- Compute Thom and Euler class
- Are these cycles boundaries?
- a problem related with path lifting property
- Bott and Tu exercise 6.5 - Reducing the structure group of a vector bundle to $O(n)$
- Cohomology groups of a torus minus a finite number of disjoint open disks
- CW-structure on $S^n$ and orientations
Related Questions in HOMOLOGY-COHOMOLOGY
- Are these cycles boundaries?
- Cohomology groups of a torus minus a finite number of disjoint open disks
- $f$ - odd implies $d(f)$ - odd, question to the proof
- Poincarè duals in complex projective space and homotopy
- understanding proof of excision theorem
- proof of excision theorem: commutativity of a diagram
- exact sequence of reduced homology groups
- Doubts about computation of the homology of $\Bbb RP^2$ in Vick's *Homology Theory*
- the quotien space of $ S^1\times S^1$
- Rational points on conics over fields of dimension 1
Related Questions in HOMOTOPY-THEORY
- how to prove this homotopic problem
- Are $[0,1]$ and $(0,1)$ homotopy equivalent?
- two maps are not homotopic equivalent
- the quotien space of $ S^1\times S^1$
- Can $X=SO(n)\setminus\{I_n\}$be homeomorphic to or homotopic equivalent to product of spheres?
- Why do $S^1 \wedge - $ and $Maps(S^1,-)$ form a Quillen adjunction?
- Is $S^{n-1}$ a deformation retract of $S^{n}$ \ {$k$ points}?
- Connection between Mayer-Vietoris and higher dimensional Seifert-Van Kampen Theorems
- Why is the number of exotic spheres equivalent to $S^7,S^{11},S^{15},S^{27}$ equal to perfect numbers?
- Are the maps homotopic?
Related Questions in EILENBERG-MACLANE-SPACES
- First cohomology of topological spaces with non abelian coefficients
- Eilenberg–MacLane space for explicit group examples
- Classifying spaces [related to Eilenberg–MacLane] for explicit group examples
- Weak product of Eilemberg MacLane spaces
- Brown representability and based homotopy classes
- Eilenberg–MacLane space $K(\mathbb{Z}_2,n)$
- "2"-group cohomology
- What is the total space of the universal bundle over $B\mathbb{Q}$?
- Reduced mod $p$ homology of a $p$-complete Eilenberg-MacLane space
- How to visualize the String(n) group?
Trending Questions
- Induction on the number of equations
- How to convince a math teacher of this simple and obvious fact?
- Find $E[XY|Y+Z=1 ]$
- Refuting the Anti-Cantor Cranks
- What are imaginary numbers?
- Determine the adjoint of $\tilde Q(x)$ for $\tilde Q(x)u:=(Qu)(x)$ where $Q:U→L^2(Ω,ℝ^d$ is a Hilbert-Schmidt operator and $U$ is a Hilbert space
- Why does this innovative method of subtraction from a third grader always work?
- How do we know that the number $1$ is not equal to the number $-1$?
- What are the Implications of having VΩ as a model for a theory?
- Defining a Galois Field based on primitive element versus polynomial?
- Can't find the relationship between two columns of numbers. Please Help
- Is computer science a branch of mathematics?
- Is there a bijection of $\mathbb{R}^n$ with itself such that the forward map is connected but the inverse is not?
- Identification of a quadrilateral as a trapezoid, rectangle, or square
- Generator of inertia group in function field extension
Popular # Hahtags
second-order-logic
numerical-methods
puzzle
logic
probability
number-theory
winding-number
real-analysis
integration
calculus
complex-analysis
sequences-and-series
proof-writing
set-theory
functions
homotopy-theory
elementary-number-theory
ordinary-differential-equations
circles
derivatives
game-theory
definite-integrals
elementary-set-theory
limits
multivariable-calculus
geometry
algebraic-number-theory
proof-verification
partial-derivative
algebra-precalculus
Popular Questions
- What is the integral of 1/x?
- How many squares actually ARE in this picture? Is this a trick question with no right answer?
- Is a matrix multiplied with its transpose something special?
- What is the difference between independent and mutually exclusive events?
- Visually stunning math concepts which are easy to explain
- taylor series of $\ln(1+x)$?
- How to tell if a set of vectors spans a space?
- Calculus question taking derivative to find horizontal tangent line
- How to determine if a function is one-to-one?
- Determine if vectors are linearly independent
- What does it mean to have a determinant equal to zero?
- Is this Batman equation for real?
- How to find perpendicular vector to another vector?
- How to find mean and median from histogram
- How many sides does a circle have?
I realize this is an old question but I thought I'd still chime in with an answer, partially because when I first encountered this idea I was also very confused by how the general construction works.
The example via the orientation bundle is good, but because the twist is low dimensional you don't really see the complexity that arises when you consider higher degree twists.
The $\infty$-Grothendieck construction is generally the right way to go, but right off the bat one has to address the question of where these bundles of spectra are supposed to live in the first place. The "correct" habitat for these generalized objects is in the tangent $\infty$-topos to spaces which I will denote by $$p:T(\infty Gpd)\to \infty Gpd \;.$$ More explicitly, the objects in $T(\infty Gpd)$ are so called spectrum objects which essentially are constructed by using a suspension operation which is "twisted" by a base space $B$ (you can read more about that here https://ncatlab.org/nlab/show/tangent+%28infinity%2C1%29-category). When $B=\ast$ you recover usual spectra. The map $p$ takes a spectrum object living over a base space $B$ and maps it to its underlying base space. So in a sense that can be made precise, there are fibers $T(\infty Gpd)_B$ of the bundle $p$ (taken at $B$) which encode the information of spectra parametrized over the space $B$.
This is all very abstract at first, but the machinery is actually very easy to utilize in practice. Most of the techniques one uses for bundles (i.e. local triviality, sheaf of sections, etc.) have analogues in this more general setting.
I'll illustrate by resonding to the question about Picard groupoid (or more generally $\infty$-groupoid). Let $R$ be a ring spectrum (at least $A_{\infty}$). Let's recall that the $\infty$-category of spectra is symmetric monoidal (as an infinity category) with respect to the smash product operation. Using that operation, we can consider modules in the same way that one considers modules via the tensor product and we can consider invertible module spectra in the same way we can consider invertible modules (i.e. there is a smash product inverse). Here though, everything is only taken up to higher homotopy coherence, so we don't have strict inverses, but only inverses up to higher homotopy coherence. So instead of organizing these invertible module spectra into a category, we are more naturally led to an $\infty$-groupoid ${\rm Pic}(R)$.
The space ${\rm Pic}(R)$ has a canonical bundle of spectra in $T(\infty Gpd)_{{\rm Pic}(R)}$ which lives over it. Via the $\infty$-Grothendiek construction (which works for spectra) this bundle is associated to the tautological $\infty$-functor $$F:{\rm Pic}(R)\to Sp\;,$$ which associates to an invertible module spectrum $L$ over $R$ to the spectrum $L$ and to morphisms morphisms of such spectra etc. Call this bundle of spectra $\lambda\to {\rm Pic}(R)$. It lives in the tangent $\infty$-topos $T(\infty Grp)$. This is a sort of universal bundle which classifies bundles of spectra with fiber $R$ in the following way. For any other space $B$, a map $\tau:B\to {\rm Pic}(R)$ specifies a twist for $R$ (i.e. an invertible $R$-module spectrum $L$). Then pullback of the universal bundle $\lambda\to {\rm Pic}(R)$ gives a bundle of spectra $E\to B$, now living over $B$.
The mapping space in $T(\infty Grp)_B$ actually forms an infinite loop space and so we have an enrichment over spectra. The spectrum of maps $Map_B(B,E)$ is then precisely the spectrum of sections of $E\to B$ and the homotopy groups of this spectrum are the $\tau$-twisted $R$-cohomology groups of $B$.
Finally, to really drive home the point as to why these objects really do behave like bundles, we need to consider the axiom of descent for an $\infty$-topos. In the present context, the key point is that if $B$ is a paracompact space and I take a good open cover $\{U_{\alpha}\}$ of $B$, then the homotopy colimit over the resulting Cech nerve is equivalent to B (by the Borsuk nerve theorem). If you take your bundle of spectra $E\to B$ and pullback by the induced maps from the nerve you simply get the trivial bundle $R\times U\to U$ (because the cover is good each of the $U_{\alpha}$'s and their intersections are contractible). Descent says that since $B$ is the colimit over the $U_{\alpha}$'s, then the bundle $E\to B$ must be the colimit of the locally trivial bundles $R\times U_{\alpha}\to U_{\alpha}$. So this bundle $E\to B$ can be glued from local data (as a bundle should). Of course if the twist has degree higher than 1, then this bundle is strictly general in the sense that one needs to take into account higher-fold intersections of the cover $\{U_{\alpha}\}$