I have question to solve by factorization.
the question is $$(a+b)x^2 + (a+2b+c)x + (b+c) = 0$$ the answer should be $$x = -a, -b.$$
i have done using it
\begin{align} (a+b)x^2 + (a+b+b+c)x + (b+c) &= 0 \\ (a+b)x^2 + ((a+b)+(b+c))x + (b+c) &= 0\\ (a+b)x^2 + (a+b)x+(b+c)x + (b+c) &= 0\\ x(a+b)[x+1] +(b+c)[x+1] &= 0\\ (x+1)(x(a+b)+(b+c)) &= 0\\ \\ x+1 &= 0\\ x(a+b)+(b+c) &= 0 \end{align}