From the following lamba calculus text it mentions:
To motivate the $\lambda$-notation, consider the everyday mathetmatical expression '$x-y$'. This can be thought of as defining either a function $f$ of $x$ or a function $g$ of $y$;
$$f(x) = x-y$$
$$g(y) = x-y$$
And later on:
Church introduced '$\lambda$' as an auxiliary symbol and wrote:
$$f = \lambda x . x - y $$ $$g = \lambda y. x - y$$
I don't really understand what motivates writing two different function here, one for f and one for g. Why isn't just one function used here such as f(x) = x - y or even f(x,y) = x - y. It seems like writing the above as two different equations is a strange way to write that "everyday equation". Could someone please explain the reasoning for this? If helpful, the whole section of text is as follows:

$f$ and $g$ are two different lambda-expressions. $f$ has $y$ as a free variable and $x$ as a bound variable whereas $g$ has $x$ as a free variable and $y$ as a bound variable. In lambda calculus, every function has one argument, so there's not really a direct way to write the function $h(x,y)=x-y.$ Instead, what we can do is something like $h:=\lambda y.f,$ or written out in full: $\lambda y.\lambda x.x-y.$ Then, for instance, $h3 = \lambda x. x-3$ and $(h3)4 = 4-3.$
So, even though $h$ is a one-argument function, it returns another one-argument function that you can plug the "second argument" into, and so $h$ does job of a two-argument function. (This phenomenon is called Currying.)
Similarly, $h':=\lambda x.g$ represents this function in a similar manner, only this time the arguments go in the "right order": $(h'4)3 = 4-3.$