I'm having some trouble interpreting this statement from wikipedia:
Gödel's first incompleteness theorem shows that for languages sufficient for doing a certain amount of arithmetic, there can be no effective deductive system that is complete with respect to the intended interpretation of the symbolism of that language. Thus, not all sound deductive systems are complete in this special sense of completeness, in which the class of models (up to isomorphism) is restricted to the intended one
From what I understand, there is no such thing as "the intended interpretation" for an arbitrary formal system. For PA, it is just convention that the "intended interpretation" is the "usual natural numbers", presumably as formalized in something like ZFC. Thus, I am having trouble understanding what "there can be no effective deductive system that is complete with respect to the intended interpretation of the symbolism of that language" means -- i.e. exactly what is meant by the "intended interpretation" here. I don't think it can mean "any possible intended interpretation", for exampe, consider the following:
Suppose that we have some semantic consequence relation $\vDash$ between models $\mathscr{U}$ and propositions $\phi$ in the language of $\mathscr{U}$. Presumably, the implied metatheory in which we define this is ZFC. So really when we say $\mathscr{U} \vDash \phi$ we mean $\vdash_{ZFC} (\mathscr{U} \vDash \phi)$.
From this, I think we can define a new syntactically defined consequence relation by setting $\Gamma \vdash_{\mathscr{U}} \phi$ if and only if $\vdash_{ZFC} (\mathscr{U} \vDash \wedge(\Gamma) \to \phi )$, and from this deduce that $\vdash_{\mathscr{U}}$ is sound and complete (with respect to this one model $\mathscr{U}$). Note that, by $\wedge(\Gamma)$ I mean the pairwise conjunction of all formulas in $\Gamma$.
Thus, if my reasoning is correct here, it seems that the deductive system given by the consequence relation $\vdash_\mathscr{U}$ is sound and complete with respect to what we by fiat make the "intended interpretation" $\mathscr{U}$. Perhaps it is not effective?
Is my argument flawed in some way, or is the wikipedia article I linked badly-worded, inaccurate, and/or using some more specific notion of "the intended interpretation" of general deductive systems that I am not aware of?
Here's the answer I think you'll find most satisfying, first up: we don't need the soundness condition at all! Goedel's original argument did require a soundness condition, but Rosser improved it: we can prove (in PA) that if $T$ is any consistent r.e. theory in the language of arithmetic extending Robinson's $Q$, then $T$ is incomplete. This is a completely formalist fact, and doesn't need to invoke models at all.
Rosser's trick, by the way, was to replace the Goedel sentence $G_T=$"I am unprovable in $T$" with the modified sentence $R_T=$"For any $T$-proof of me, there is a shorter $T$-disproof of me." Reasoning inside PA, if $T\vdash R_T$ then let $\pi$ be the shortest $T$-proof of $R_T$. There are only finitely many $T$-proofs shorter than $\pi$, so $T$ can "check them all" - if one of them is a proof of $R_T$ then $T$ is inconsistent, and if none of them $R$ then in this way $T$ disproves $R_T$, so either way $T$ is inconsistent. Meanwhile if $T\vdash \neg R_T$, then there is a shortest proof $\pi$ of $\neg R_T$. If $T$ is consistent, then there is no $T$-proof of $R_T$, in particular no $T$-proof of $R_T$ shorter than $\pi$. Again by checking all the finitely many $T$-proofs shorter than $\pi$, $T$ verifies that if there is a $T$-proof of $R_T$ then it is longer than $\pi$; and this is a $T$-proof of $R_T$! So $T$ is inconsistent.
So for $T$ to be consistent, $R_T$ must be undecidable in $T$.
You've also made a serious mistake regarding your "$\vdash_\mathcal{U}$".
First of all, if we're doing everything formalistically (that is, not working in a background model of ZFC), then we can't really have a model $\mathcal{U}$ (we can't really talk about "actual models" without fixing a background universe of set theory). So instead, $\mathcal{U}$ should really be a definable model. E.g. any model of ZFC has an object it thinks is the natural numbers; there is a single formula which picks out the relevant object in each model of ZFC. This isn't a huge issue, but it's worth pointing out.
Now to the main point: the relation "$\varphi\vdash_\mathcal{U}\psi$" is not effective (well, its deduction rules are effective, but its set of tautologies isn't; what I really mean is not decidable - but note that for complete systems, effective = decidable) or complete, even for reasonably nice $\varphi,\psi,$ and $\mathcal{U}$. For instance, take $\mathcal{U}$ to be "the natural numbers" and $\varphi$ to be $\top$; then $\varphi\vdash_\mathcal{U}\psi$ iff $ZFC$ proves "The natural numbers satisfy $\psi$." But the set of arithmetic consequences of ZFC is not decidable or complete!
We can go more Platonistic: working within a universe of sets $V$, it is certainly the case that for each structure $\mathcal{U}\in V$ and each $\varphi$, either $V\models(\mathcal{U}\models\varphi)$ or $V\models(\mathcal{U}\models\neg\varphi)$, so the system is complete; however, now it is not effective since truth in $V$ cannot be effectively determined.
Now on to the "intended interpretation" issue.
Not all theories have intended interpretations in any sense. However, if $T$ is any theory including some theory of arithmetc $S$ (e.g. $T$ might have other symbols - a model of $T$ might look like a model of $S$ together with some other junk), then we can say that a "standard model" of $T$ is one where the $S$-part is the actual natural numbers. This definition is phrased in ZFC, so different models of ZFC may have different things they think are the actual natural numbers. ZFC now proves "If $S$ is sufficiently strong and $T$ has standard models (this is a soundness condition), then the set of arithmetic consequences of $T$ is not r.e. and complete."
Now I'm mostly a formalist, but I'd argue that we have to begin math with a thing we consider the "true natural numbers" to a certain extent, so I'm comfortable referring to the intended interpretation of a theory in the language of arithmetic; but even if one isn't, Goedel's theorem can be formulated and proved in ZFC as I've described above.