Since multiplication is such a basic algorithm in math we rarely stop to think about what it really is about, so please, help me understand?
When we multiply two numbers we are basically increasing the number of units of one number by the other. When we calculate factorials for example, why is it we multiply one number by the other?
If I want to know how many ways $5$ people can stand in line, why would I need to multiply $5 \times 4 \times 3 \times 2 \times 1$ if I just want the total number, which seems like I should add them all? In other words why is it I need the number $5$ increased by $4$ units (multiplication), then $3$ units, then $2$, etc?
What does it mean to multiply?!
The simplest sort of multiplication works like this: $$ \begin{array}{ccccc} \bullet & \bullet & \bullet & \bullet & \bullet \\ \bullet & \bullet & \bullet & \bullet & \bullet \\ \bullet & \bullet & \bullet & \bullet & \bullet \end{array} $$ You have three horizontal rows each with five things, so $3\times5 = 5+5+5=15$ things,
or you have five vertical columns each with three things, so $5\times 3= 3+3+3+3+3=15$ things.
Now consider your five people standing in a queue. Their names are A, B, C, D, E.
Who is first in the queue? It's one of the five. Who is second in the queue? It's one of the other four: $$ \begin{array}{ccccc} A\text{ is first} & B \text{ is first} & C\text{ is first} & D\text{is first} & E\text{ is first} \\ \hline AB & BA & CA & DA & EA \\ AC & BC & CB & DB & EB \\ AD & BD & CD & DC & EC \\ AE & BE & CE & DE & ED \end{array} $$ So for each possible answer to "who is first", there are four possible answers to "who is second", and thus $5\times 4$ possibilities.
Now as "who is third?". It's one of the three remaining possibilities after the first two. If the first two are $AB$, then you can have $ABC$ or $ABD$ or $ABE$. If the first two are $EC$, then you can have $ECA$ or $ECB$ or $ECD$. And so on. For every one of the $20$ possibilities in the table above, there are three possibilities, so you get a list three times as long as the table above, thus $5\times4\times3=60$.
And so on.