After a brief checkout on poisson distribution i understand that poisson has results in outomes that can be described as success or failures
And also that poisson probability is found by
P(x; μ) = (e-μ) (μx) / x!
What am not getting is how to interprete this
X ∼ POIS(6)
A small thought would be that x iis normally distributed as a posson of 6 or how do i go about it since am later suposed find the probability of x=0
But i would like to understand what X ∼ POIS(6) means
David Mitra answered your question correctly in the comments.
In general $X \sim Dist(a,b,c,...)$ means X is a random variable whose distribution is "Dist" with parameters a,b,c,...
In this case the Poisson distribution only has one parameter, $\mu$, which is equal to 6.