Uniform convergence of a sequence $f_n(x)=n/(x+n)$

213 Views Asked by At

Show that the sequence $\{f_n\}$ of function where $f_n(x)=n/(x+n)$, is uniformly convergent in $[0,k]$ whatever $k$ may be, but not uniformly convergent in $[0,\infty)$.

The sequence is point wise convergent $\forall x\geq 0$, $$f(x)=1\hspace{1 cm} \forall x\geq0$$

How to proceed further?

1

There are 1 best solutions below

0
On BEST ANSWER

The pointwise limit is $f(x)=1$.

In $[0,k]$ we have $$|f(x)-f_n(x)|=\left|1-\frac{n}{x+n}\right|=\frac{x}{x+n}$$

The map $$x\mapsto\frac{x}{x+n}$$ is an increasing function on $[0,k]$. So the maxima of this function (which occurs at $x=k$) is $\frac{k}{k+n}$.

So $$\lim_{n\to\infty}(\sup_{x\in[0,k]}|f(x)-f_n(x)|)= \lim_{n\to\infty}\frac{k}{k+n}=0$$ Hence $f_n\rightarrow f$ uniformly in $[0,k]$.