Setup
Let $M$ be a closed, orientable, smooth manifold, and $\alpha\in H^2(M)$. Further, let $N\subset M$ be a closed, orientable submanifold that is Poincare dual to $\alpha$, and let $E\rightarrow M$ be the complex line bundle whose Euler class is $\alpha$. Finally, let $s:M\rightarrow E$ be a section transverse to the zero section, and $Z=\{m\in M\mid s(m)=0\}$.
Question
Are $N$ and $Z$ cobordant?
Context
I know that $Z$ is also Poincare dual to $\alpha$, but I am wondering if $Z$ is "unique up to cobordism".
In a sense, it all boils down to the fact that the same space ($\mathbb CP^\infty$) is both $K(\mathbb Z,2)$ and $BSO(2)$:
Since $\mathbb CP^\infty$ is $K(\mathbb Z,2)$, we have $H^2(X)=[X,\mathbb CP^\infty]$. To get a realization of a class in $H^2(M)$ by a submanifold take the preimage of $\mathbb CP^{N-1}$ under a map $M\to\mathbb CP^N$ corresponding to the class [and transversal to $\mathbb CP^{N-1}$).
Moreover, any codimension 2 cooriented submanifold $Z\subset M$ is a preimage of $\mathbb CP^{N-1}\subset\mathbb CP^N$. Indeed:
If we have two such realizations of the same class, we get a homotopy $M\times[0;1]\to CP^N$ — again make this map transversal and take the preimage of $\mathbb CP^{N-1}$ — that's a cobordism you're looking for.