S = $ \begin{Bmatrix} \begin{bmatrix} 1 \\ 1 \\ 1 \\ \end{bmatrix} \begin{bmatrix} 5 \\ -1 \\ 2 \\ \end{bmatrix} \end{Bmatrix} $
So after doing some work I get:
$v_1 = $ $ \begin{bmatrix} 1 \\ 1 \\ 1 \\ \end{bmatrix} $
$v_2 = 1/5$ $ \begin{bmatrix} 24 \\ -6 \\ 9 \\ \end{bmatrix} $
But the answer is the following:
$ \begin{Bmatrix} \begin{bmatrix} 1 \\ 1 \\ 1 \\ \end{bmatrix} \begin{bmatrix} 3 \\ -3 \\ 0 \\ \end{bmatrix} \end{Bmatrix} $
So is my $v_2$ wrong? Am I missing a step?
Perhaps here is the mistake:
$$u_1=\frac{v_1}{\left\|v_1\right\|}=\frac1{\sqrt3}\begin{pmatrix}1\\1\\1\end{pmatrix}$$
and now
$$v_2-(v_2\cdot u_1)u_1=\begin{pmatrix}5\\\!-1\\2\end{pmatrix}-\frac136\begin{pmatrix}1\\1\\1\end{pmatrix}=\begin{pmatrix}3\\\!-3\\0\end{pmatrix}$$