Use induction to show that $3^n >n^3$ for $n≥4$. (Note that you have to start at $n=4$ as the result isn't true for $n=3$ !)
I am very new to using induction, but as I understand it I have to do the following:
- Show that it is true for the base case, when $n=4$, so $ 3^4 > 4^3$, which is indeed true.
- Assume that for $n=k$, that $3^k>k^3$ for $k\ge 4$ (The induction hypothesis).
- Then you show that the hypothesis being true at some k implies that it holds at $n=k+1$.
So what I have to do is show that $3^{k+1}>(k+1)^3$.
I don't know where to begin.
I know that $(k+1)^3 = k^3+3 k^2+3 k+1$ and that $3(3^k) = 3^{k+1}$ but no idea how to proceed.
Hint: prove that $3k^3>(k+1)^3$ for $k \geq 4$.