Use the definition of a limit to prove the following: $$\lim_{x\to0}\frac{\cos x}{x^{2}}=\infty$$
I'm trying to prove that: $$\forall E >0\,\,,\exists\delta>0 \\~\\ 0<|x|<\delta\Longrightarrow\frac{\cos x}{x^{2}}>E$$ I know $-1\leq \cos x\leq1$ and $\frac{1}{x^{2}}>\frac{1}{\delta^{2}}$ ,But I can't put it together.
For any $\;E>0\;,\;$ take $\;\delta=\min\left\{\frac\pi3,\frac1{\sqrt{2E}}\right\}>0\;$.
Then, if $\;0<|x|<\delta\;,\;$ you have $$\cos x>\frac12\quad\text{and}\quad\frac1{x^2}>2E\;.$$ Therefore, $\;\dfrac{\cos x}{x^2}>E\;$.