use the epsilon delta definition of limits to show that:
$$\lim_{x\to 0} \sqrt{x+1} = 1$$
I am familiar with epsilon delta proofs, but i am not sure how to approch this problem.
2026-04-06 04:09:26.1775448566
use the epsilon delta definition to show $\lim_{x\to 0} \sqrt{x+1} = 1$
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Hint: $\sqrt{x+1}-1=\frac{x}{\sqrt{x+1}+1}$