Use three 11's and various math symbols to make an equation equal to 6

Question

The puzzle is to use the following symbols $$+,\;-,\;*,\;/,\;(\;,\;),\;!, \;\sqrt(\cdot)$$ in order to make a valid equation out of $$11~~~~~~11~~~~~~~11 = 6.$$

(There are three elevens with space in between for symbols).

This is part of a general series of questions about using any three integers in place of the elevens, but this case has me stumped.

So the question is to determine if it is possible to form a valid equation or how to prove it is not possible in an elegant way that avoids checking all possible cases.

Answer 1

$\large 6=\left( \sqrt{\sqrt{\frac{11+11!!!}{11}}}\right)\LARGE!$
where n!!! = n(n-3)(n-6)... is triple factorial

Answer 2

$11+11+11\neq 6$

EDIT: Hmm, I suppose that isn't strictly an "equation".

Answer 3

If we're allowed multifactorials as in @Egor's answer, then we can make any $n > 3$ via $$ \left(\tfrac{\sqrt{n\times n}\underbrace{!!!\cdots !}_{n-3 \text{ times}}} { n} \right) !$$