I just took a quiz and one of the problems was to get the derivative of $f(x) = (4x^2-2)^3$.
I used the chain rule and got $f'(x) = 24x(4x^2-2)^2$.
However, plugging it into the derivative function in a TI-89 returns $f(x) = 96x(2x^2-1)^2$. Which is right? Me or the calculator?
$$y' = 24x(4x^2-2)^2$$ $$y'=24x[2(2x^2-1)]^2$$ $$y'=24x[2^2(2x^2-1)^2]$$ $$y'=96x(2x^2-1)^2$$ both are right