Using Green's Theorem to find the flux

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$F(x,y)=\langle y^2+e^x,x^2+e^y\rangle$. Using green's theorem in its circulation and flux forms, determine the flux and circulation of $F$ around the triangle $T$, where $T$ is the triangle with vertices $(0,0),(1,0),$ and $(0,1)$, oriented counterclockwise.

My Try:

$f=y^2+e^x$

$g=x^2+e^y$

$$\frac{\partial f}{\partial y}=2y$$ $$\frac{\partial g}{\partial x}=2x$$ $$\int F\cdot dr=\int\int_R(2x-2y)dA$$ $$\int^{1}_{0}\int_{0}^{1-x}(2x-2y)dydx=0$$ My quesiton: Is my above attempt correct? Because I got the answer as $0$

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The result is correct indeed we have that the region is symmetric with respect to $y=x$ and the integral for $2x$ is equal to the integral for $2y$ that is

$$\int\int_R 2x\,dA=\int\int_R2y\,dA \implies \int\int_R(2x-2y)dA=0$$