$1458^n = 2^n / 9$
I'm told to find the value of $n$. How to do that?
It is my first time encountering this type of problem when I can't find make every number a constant . What do I do here . Can I get a hint ? Thanks in advance
(2 x 3^6)^n x 3^2 = 2^n
$$1458^n=\frac{2^n}{9}$$
$$729^n\cdot 2^n=\frac{2^n}{9}$$
$$729^n=\frac{1}{9}$$
$$9^{3n}=9^{-1}$$
$$3n=-1$$
$$n=-\frac{1}{3}$$