Using the answer from one quadratic to solve another quadratic

Question

a)Factorise the expression $2x^2-3x-35=(2x+7)(x-5)$

b)Use your answer to part a to solve the equation $2(2x-1)^2-3(2x-1)-35$

How would I use my answer from a to solve b? I don't see how it helps me solve it.

Answer 1

The second expression is similar to first, just x has been replaced by 2x-1, so in your initial answer{ (2x+7)(x-5) }, replace x with 2x-1 and you should get the answer.

Answer 2

Hint:

substitute $2x-1=y$ i the second equation, than use the factorization of the first equation.