If A is unitary, then $$AA^* = A^*A = I, and\ A^* = A^{-1}$$
I want to see this explicitly for a very simple unitary matrix, say, take the column vector A = (1,0,0) and we regard this as a 3x1 orthogonal matrix.
But $AA^*$ gives a 3x3 matrix which is not the identity matrix but rather a matrix with a 1 in the entry $a_{11}$ and zeros everywhere else in the matrix.
So, where did things go "wrong"?
Thanks,
You need that $A$ is a square matrix, not a column.
Edit: Omnomnomnom was first :)