Valid proof by induction for modulus of a product of complex numbers

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I want to prove that $$|z_1 z_2 z_3\cdots z_n|=|z_1| | z_2| |z_3|\cdots|z_n|$$

Now this really feels like something I can just throw induction at.

Base case: $n=2$.

$|z_1 z_2|=|z_1| |z_2|$ follows directly from expressing these numbers in exponential form.

Induction hypothesis:

Now assume that for $\forall k$, we can say that

$|z_1 z_2 z_3\cdots z_k|=|z_1| | z_2| |z_3|\cdots|z_k|$.

Inductive step:

Call the product of the first terms $w$

$$|z_1 z_2 z_3\cdots z_k z_{k+1}|=| w \space z_{k+1}|=|w||z_{k+1}|$$

Now use the induction hypothesis:

$$|w||z_{k+1}|=|z_1| | z_2| |z_3|\cdots|z_k||z_{k+1}|.$$

The aforementioned theorem holds by the principle of induction. QED

Modulus really feels like a homomorphism like this, did I do my proof correctly, should I elaborate? Is my writing clear? Any tips or recommendations? I really feel induction proofs are a bit rigid sometimes, the interesting ones are the ones where the inductive step isn't straightforward at all and requires some extra skill or inspiration.

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Your solution is perfect. There is nothing to add. Perhaps only this for $n=2$:

$$ |zw| = \sqrt{zw \cdot \overline{zw}} = \sqrt{z\overline{z}}\cdot \sqrt{w\overline{w}} = |z||w|$$