Two random variables, $Y$ and $Z$:
$Y = 0.5+0.6X$
$Z = 0.2+0.3X$
where $X$ is another random variable. You can treat the variance $var(X)$ as a given constant. It may help to give $var(X)$ a name, $()=^2$.
$var(Y) = 1/2 + (9/25)^2$
$var(Z) = 2/25 + (9/100)^2$
$Cov(Y,Z) = (9/50)^2$
$Cov(X,Z) = (3/10)^2$
$Cov(X,Y) = (3/5)^2$
Also, how would I find the $Corr(Y,Z)$, $Corr(X,Z)$, and $Corr(X,Y)$?
Firstly. If $Y=0.5+0.6X$ and $\mathsf {Var}(X)=\sigma^2$ , then $\mathsf{Var}(Y)=0.36\sigma^2$
Because $\mathsf {Var}(a+bX) ~=~ b^2~\mathsf{Var}(X)$ when $a,b$ are constants.
Similarly: $\mathsf {Cov}(a+bX, c+dX) ~=~ bd~\mathsf{Var}(X)$
Revisit all your calculations.
Secondly The correlation coefficient is defined as:
$$\mathsf {Corr}(U,V) ~=~ \dfrac{\mathsf {Cov}(U,V)}{\sqrt{~\mathsf{Var}(U)~\mathsf{Var}(V)~}}$$
Just substitute as appropriate.