Here is the identity I need to prove:
$\vec\nabla\cdot(\vec\nabla f\times (\vec r f)) = 0$, where $f$ is a smooth scalar field and $\vec r$ is the position vector.
Some tips would be brilliant!
Here is the identity I need to prove:
$\vec\nabla\cdot(\vec\nabla f\times (\vec r f)) = 0$, where $f$ is a smooth scalar field and $\vec r$ is the position vector.
Some tips would be brilliant!
Copyright © 2021 JogjaFile Inc.