Vector operations.

Question

At 12:00 pm, a spaceship is at position [3,2,4]km away from the origin with respect to some 3 dimensional co ordinate system. The ship is travelling with velocity [-1,2,-3]km/h What is the location of the spaceship after 2 hours have passed?

Answer 1

Initial position: $$[3,2,4]$$ Velocity: $$[-1,2,-3]$$ So, in $2$ hours, it travels $-2,4$ and $-6$ kms resp. in $3-D$ co-ordinate system.

It's final position becomes: $$[3-2,2+4,4-6]=[1,6,-2]$$

Answer 2

Hint: Use the definition of velocity in a constant velocity movement$$\vec v={\vec x_2-\vec x_1\over t_2-t_1}$$