A box weighting 294N is sitting on a ramp. If the ramp is inclined at an angle of 25 degrees to the horizontal, and there is a 40N force of friction, calculate the amount of force that must be applied parallel to the ramp to hold the box in place.
2026-04-01 11:10:47.1775041847
Vectors and Forces
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Take component of forces normal and parallel to the incline. Normal Force would cancel any component normal to the incline. The remaining Forces are :
$40N$ opposite to the direction you want to move.
$296\sin25^\circ N$ down the incline.
$F$ you are applying upwards.
As friction is smaller than weight component it can only act upwards.
$F+40N=296\sin25^\circ N$