When two vectors are sketched from a single point, the angle between them is θ. Show that the size of their vector summation is given in the expression: $ \sqrt{A^2 + B^2 +2ABcosθ} $.
Any suggestions on how one might tackle this one?
When two vectors are sketched from a single point, the angle between them is θ. Show that the size of their vector summation is given in the expression: $ \sqrt{A^2 + B^2 +2ABcosθ} $.
Any suggestions on how one might tackle this one?
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Notice that $\|A+B\|^2=\|A\|^2+2\langle A,B\rangle+\|B\|^2$ and $\langle A,B\rangle\cdot \|A\|\cdot\|B\|=\cos(\theta)$.